XOOPS中修正获取真实用户名的Bug (Fixed)

调用XOOPS中返回用户姓名时，通过getUnameFromId返回用户姓名时，如果希望返回用户真实姓名时，但是当用户没有填写真实姓名的时候返回的将会是空串，下面这个Hack就用于解决这个问题，当用户没有填写真实姓名时返回用户登录名。

htdocs\kernel\user.php文件，139行附近将getUnameFromId函数做如下修改即可：

原函数：

   1: function getUnameFromId( $userid, $usereal = 0 )

   2: {

   3:     $userid = intval($userid);

   4:     $usereal = intval($usereal);

   5:     if ($userid > 0) {

   6:         $member_handler =& xoops_gethandler('member');

   7:         $user =& $member_handler->getUser($userid);

   8:         if (is_object($user)) {

   9:             $ts =& MyTextSanitizer::getInstance();

  10:             if ( $usereal ) {

  11:                 return $ts->htmlSpecialChars($user->getVar('name'));

  12:             } else {

  13:                 return $ts->htmlSpecialChars($user->getVar('uname'));

  14:             }

  15:         }

  16:     }

  17:     return $GLOBALS['xoopsConfig']['anonymous'];

  18: }

修改之后函数为：

   1:    2:    3:    4:    5:    6:    7:    8:    9:   10:   11:   12:   13:   14:   15:   16:   17:   18:   19:   20:   21:   22:

function getUnameFromId( $userid, $usereal = 0 )
 {
 $userid = intval($userid);
 $usereal = intval($usereal);
 if ($userid > 0) {
 $member_handler =& xoops_gethandler('member');
 $user =& $member_handler->getUser($userid);
 if (is_object($user)) {
 $ts =& MyTextSanitizer::getInstance();
 if ( $usereal ) {
 if(trim($user->getVar('name')) != '') {
 return $ts->htmlSpecialChars($user->getVar('name'));
 } else {
 return $ts->htmlSpecialChars($user->getVar('uname'));
 }
 } else {
 return $ts->htmlSpecialChars($user->getVar('uname'));
 }
 }
 }
 return $GLOBALS['xoopsConfig']['anonymous'];
 }